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Solved
Intersection points of a polynomial
Find the intersection points of a polynomial, given by its vector of coefficients with the X-axis and the Y-axis. Input: a poly...
7 months ago
Solved
Leap Year
According to Gregorian Calender(which is in use now, in many countries),decide whether a given year is a leap year or not. Give...
8 months ago
Solved
What kind of triangle?
Write a function named check_triangle that receives three positive integers as input: a, b, and c. These three numbers are inte...
8 months ago
Solved
Laws of motion 4
Given the initial velocity 'u', final velocity 'v' and acceleration 'a', find the distance travelled.
1 year ago
Solved
Sum of series
a(n) = n^2 - (n-1)^2 find the summation of the series upto n i.e. a(1)+a(2)+...+a(n)
1 year ago
Solved
Sum of series VII
What is the sum of the following sequence: Σ(km^k)/(k+m)! for k=1...n for different n and m?
1 year ago
Solved
Sum of series VI
What is the sum of the following sequence: Σk⋅k! for k=1...n for different n?
1 year ago
Solved
Sum of series V
What is the sum of the following sequence: Σk(k+1) for k=1...n for different n?
1 year ago
Solved
Sum of series III
What is the sum of the following sequence: Σ(2k-1)^3 for k=1...n for different n?
1 year ago
Solved
Sum of series II
What is the sum of the following sequence: Σ(2k-1)^2 for k=1...n for different n?
1 year ago
Solved
Sum of series I
What is the sum of the following sequence: Σ(2k-1) for k=1...n for different n?
1 year ago
Solved
Sum of series IX
What is the sum of the following sequence: Σ 1/k! for k=1...n for different n?
1 year ago
Solved
Sum of series IV
What is the sum of the following sequence: Σ(-1)^(k+1) (2k-1)^2 for k=1...n for different n?
1 year ago
Solved
Pascal's Triangle
Given an integer n >= 0, generate the length n+1 row vector representing the n-th row of <http://en.wikipedia.org/wiki/Pascals_t...
1 year ago
Solved
Times 2 - START HERE
Try out this test problem first. Given the variable x as your input, multiply it by two and put the result in y. Examples:...
1 year ago
