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Question
二元函数绘图并求极值。
函数g=0.2*sqrt(2*pi*b/(a.^2-1))*log(sqrt(a+(a.^2+b.^2))/(1+sqrt(1+b.^2)))做出三维图形，并求出极值，其中0<=x<=10,0<=y<=10.
3 years ago | 1 answer | 0
