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为什么用fittype函数自定义正态分布密度函数去进行拟合，估计出来的参数和用normfit估计出来的参数，相差特别多呢？。
你的数据问题？ 我的试验： x=normrnd(10,10,1,1e3); [yi,xi]=ksdensity(x); normm=fittype(@(c,d,x) 0.39894228.*exp(-0.5.*(x-c).^2/d.^2)/d);...
3 years ago | 0
| accepted
