Statistics
0 Questions
1 Answer
RANK
11,765
of 300,857
REPUTATION
4
CONTRIBUTIONS
0 Questions
1 Answer
ANSWER ACCEPTANCE
0.00%
VOTES RECEIVED
0
RANK
of 21,097
REPUTATION
N/A
AVERAGE RATING
0.00
CONTRIBUTIONS
0 Files
DOWNLOADS
0
ALL TIME DOWNLOADS
0
RANK
of 171,361
CONTRIBUTIONS
0 Problems
0 Solutions
SCORE
0
NUMBER OF BADGES
0
CONTRIBUTIONS
0 Posts
CONTRIBUTIONS
0 Public Channels
AVERAGE RATING
CONTRIBUTIONS
0 Discussions
AVERAGE NO. OF LIKES
Feeds
如何拟合双参数weibull和K分布,求出参数并进行KS检验。
fx=@(b,x)b(4)*((x-b(3))/b(1)).^(b(2)-1).*exp(-((x-b(3))./b(1)).^b(2)); b=[8.142773896 -2.525778442 15.50968285 391.7327885];...
3 years ago | 0
| accepted

