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fatal error: rtwtypes.h: No such file or directory #include "rtwtypes.h"
My model has some reference model in accelerator mode. When I update the model, I get the error fatal error: rtwtypes.h: No suc...

mer än ett år ago | 1 answer | 1

1

answer

Question


How to reduce start time of my simulink model
I want to reduce the time to start the simulink model. I found the compilation is taking more time (5 minutes) before starting t...

mer än ett år ago | 1 answer | 0

1

answer

Question


Simulink start takes long time to compile
I have a simulink model, with a few reference models. When I 'Update' the model, it is so fast.. But when I 'Run' the model, com...

mer än ett år ago | 2 answers | 0

2

answers

Question


Code generatable option to read a *.tif file using MATLAB/Simulink
Hi.. Can someone help me to identify a code generatable API/block for *.tif image reading in MATLAB/Simulink.. Thanks in Advanc...

nästan 2 år ago | 1 answer | 0

1

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Is there a way to stop simulation, when an error case is met.
In simulink, if an error occurs (eg: invalid input parameters), is there a way to stop simulation at that point. I know below o...

nästan 2 år ago | 1 answer | 0

1

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Find area of a polygon portion of an Image (Code generatable code)
I want to calculate the area of the a portion of binary image, as shown in example. I know, there are different different opt...

nästan 2 år ago | 1 answer | 0

1

answer

Question


Split a rhombus in an image into four through centroid
I need to find the area of 4 partitions of the rhombus like image. Thank you in advance for the support. The partition should b...

nästan 2 år ago | 2 answers | 0

2

answers

Question


Linear solving without fixing the input
Inputs - a, b Output - d,c (where d equals c) AND x,y where dx+cy = 0 In general, I have 2 random inputs. I need the outpu...

ungefär 2 år ago | 1 answer | 0

1

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Question


linear inequality constrains based on absolute values
Please help me to define the inequality constrains for quadprog in the below scenario x+y <= 0.1*abs(x) x+y >= -0.1*abs(x)

ungefär 2 år ago | 2 answers | 0

2

answers