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Aktaruzzaman shuvo


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Question


how to find slope of sin^-1(x) curve at a given point x=sqrt(1/2)? the code of forward differentiation doesn't work for me
h=0.01 x = -1:h:1; y=asind(x); for i=1:length(x)-1 dy(i)=(y(x(i+1))-y(x(i)))/h; end

4 years ago | 2 answers | 0

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Question


why it shows no curve in this code?
f=@(x)(2+cos(x.^2))/(3*x.^2+4-x); y=f(x); plot (x,y)

4 years ago | 1 answer | 0

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