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use newton raphson method to find roots of exp(-x)-x
clear all; clc; n = 11; x = zeros(1,numel(n)); ea = zeros(1,numel(n)); g=@(x) exp(-x); f=@(x) exp(-x)-x; true_root=0.56...

11 månader ago | 0 answers | 0

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Question


simple Fixed Point Iteration
clear all; clc; x(1)=0; g=@(x) exp(-x); f=@(x) exp(-x)-x; true_root=0.56714329; disp('--------------------------------...

11 månader ago | 1 answer | 0

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