Problem 487. Find perfect placement of non-rotating dominoes (easier)

list = [1 2
        4 3
        2 4

order = [1 3 2]

yields: [1 2][2 4][4 3]
    or: abs(2-2) + abs(4-4)
    or:        0 + 0
    or: 0

Solution Comments

Problem Recent Solvers381

Suggested Problems

• Back to basics 21 - Matrix replicating

  1788 Solvers

• Multiply a column by a row

  822 Solvers

• Given a window, how many subsets of a vector sum positive

  870 Solvers

• Check if number exists in vector

  13794 Solvers

• Bit Reversal

  1609 Solvers

More from this Author51

• Project Euler: Problem 6, Natural numbers, squares and sums.

  2535 Solvers

• Implement Solitaire cipher for N long deck.

  17 Solvers

• Poker Series 01: isStraightFlush

  121 Solvers

• Make blocks of color

  55 Solvers

• Project Euler: Problem 10, Sum of Primes

  2088 Solvers