Problem 42778. GJam March 2016 IOW: Polynesiaglot Medium

Created by Richard Zapor

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>This Challenge is derived from</w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://code.google.com/codejam/contest/8274486/dashboard#s=p2\"><w:r><w:t>GJam March 2016 Annual I/O for Polynesiaglot</w:t></w:r></w:hyperlink><w:r><w:t>. This is a subset of small set 2. The max Qraw is 2^50 (&lt;1.1259e15) for C[1,50], V[1,50], L[1,15].</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The GJam story goes that words are such that consonants are always followed by a vowel. Determine the number of possible words of length L using C consonants and V vowels. The final Q is to be modulo of the prime 1E9+7.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Input:</w:t></w:r><w:r><w:t> [C V L] , C[1,50], V[1,50], 1&lt;=L&lt;=15</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Output:</w:t></w:r><w:r><w:t> [Q] max Qraw is 2^50 (&lt;1.1259e15); Q=mod(Qraw,1E9+7)</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Examples:</w:t></w:r><w:r><w:t> [C V L] [Q]</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[[1 1 4] [5] {aaaa,aaba,abaa,baaa,baba} invalid are {bbaa, aaab} \n[1 2 2] [6] {aa,ae,ba,be,ee,ea} invalid are {ab,eb,bb}]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t></w:t></w:r><w:hyperlink w:docLocation=\"http://code.google.com/codejam\"><w:r><w:rPr><w:b/></w:rPr><w:t>Google Code Jam 2016 Open Qualifier: April 8, 2016</w:t></w:r></w:hyperlink></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Theory:</w:t></w:r><w:r><w:t> This is a large value problem, on the order of (C+V)^L, thus brute force will not work. This is also a probability tree type problem. Tree calculations can be reduced to a linear in L evaluation. Inspection shows Q(1)=V, Q(2)=V^2, L=3 Q(3)=V^3+V*C*V+C*V^2 = V*Q(L-1)+V*C*Q(L-2)+C*Q(L-1). There are no Cs at the Q1 level since can not end in a C. Qnext=f(Q(-1),Q(-2)). Qfinal=Q+C*Q(-1)</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[Q3 V C\nQ2 V C V\nQ1 V V V\n\n This medium challenge has eps(Qraw) <0.25 so normal matlab doubles work. For the unbounded case a solution method is to convert this Challenge algorithm to Matlab BigInteger java calls. Solution sizes are on the order of (C+V)^L with the large case being C=50,V=50,L=500.]]></w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

This Challenge is derived from <a href = "http://code.google.com/codejam/contest/8274486/dashboard#s=p2">GJam March 2016 Annual I/O for Polynesiaglot</a>. This is a subset of small set 2. The max Qraw is 2^50 (&lt;1.1259e15) for C[1,50], V[1,50], L[1,15].The GJam story goes that words are such that consonants are always followed by a vowel. Determine the number of possible words of length L using C consonants and V vowels. The final Q is to be modulo of the prime 1E9+7.Input: [C V L] , C[1,50], V[1,50], 1&lt;=L&lt;=15Output: [Q] max Qraw is 2^50 (&lt;1.1259e15); Q=mod(Qraw,1E9+7)Examples: [C V L] [Q]<pre class="language-matlab">[1 1 4] [5] {aaaa,aaba,abaa,baaa,baba} invalid are {bbaa, aaab} 
[1 2 2] [6] {aa,ae,ba,be,ee,ea} invalid are {ab,eb,bb}
</pre><a href = "http://code.google.com/codejam">Google Code Jam 2016 Open Qualifier: April 8, 2016</a>Theory: This is a large value problem, on the order of (C+V)^L, thus brute force will not work. This is also a probability tree type problem. Tree calculations can be reduced to a linear in L evaluation. Inspection shows Q(1)=V, Q(2)=V^2, L=3 Q(3)=V^3+V*C*V+C*V^2 = V*Q(L-1)+V*C*Q(L-2)+C*Q(L-1). There are no Cs at the Q1 level since can not end in a C. Qnext=f(Q(-1),Q(-2)). Qfinal=Q+C*Q(-1)<pre class="language-matlab">Q3 V C
Q2 V C V
Q1 V V V
</pre><pre> This medium challenge has eps(Qraw) &lt;0.25 so normal matlab doubles work. For the unbounded case a solution method is to convert this Challenge algorithm to Matlab BigInteger java calls. Solution sizes are on the order of (C+V)^L with the large case being C=50,V=50,L=500.</pre>

This Challenge is derived from <http://code.google.com/codejam/contest/8274486/dashboard#s=p2 GJam March 2016 Annual I/O for Polynesiaglot>. This is a subset of small set 2. The max Qraw is 2^50 (<1.1259e15) for C[1,50], V[1,50], L[1,15].

The GJam story goes that words are such that consonants are always followed by a vowel. Determine the number of possible words of length L using C consonants and V vowels. The final Q is to be modulo of the prime 1E9+7.

*Input:* [C V L] , C[1,50], V[1,50], 1<=L<=15

*Output:* [Q] max Qraw is 2^50 (<1.1259e15); Q=mod(Qraw,1E9+7)

*Examples:* [C V L] [Q]

[1 1 4] [5] {aaaa,aaba,abaa,baaa,baba}  invalid are {bbaa, aaab} 
  [1 2 2] [6] {aa,ae,ba,be,ee,ea} invalid are {ab,eb,bb}

*<http://code.google.com/codejam Google Code Jam 2016 Open Qualifier: April 8, 2016>*

*Theory:* This is a large value problem, on the order of (C+V)^L, thus brute force will not work. This is also a probability tree type problem. Tree calculations can be reduced to a linear in L evaluation. Inspection shows Q(1)=V, Q(2)=V^2, L=3 Q(3)=V^3+V*C*V+C*V^2 = V*Q(L-1)+V*C*Q(L-2)+C*Q(L-1).  There are no Cs at the Q1 level since can not end in a C. Qnext=f(Q(-1),Q(-2)). Qfinal=Q+C*Q(-1)

Q3    V          C
  Q2  V   C       V
  Q1 V   V       V

This medium challenge has eps(Qraw) <0.25 so normal matlab doubles work. For the unbounded case a solution method is to convert this Challenge algorithm to Matlab BigInteger java calls. Solution sizes are on the order of (C+V)^L with the large case being C=50,V=50,L=500.

Solve

Solution Stats

18 Solutions
7 Solvers

Last Solution submitted on Apr 25, 2023

Last 200 Solutions

Problem Comments

Solution Comments

Show comments

Problem Recent Solvers7

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Problem 42778. GJam March 2016 IOW: Polynesiaglot Medium

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers7

Suggested Problems

More from this Author260

Problem Tags

Community Treasure Hunt

Problem 42778. GJam March 2016 IOW: Polynesiaglot Medium

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers7

Suggested Problems

More from this Author260

Problem Tags

Community Treasure Hunt

Players