you might want to make a case that's not a magic square, considering the properties of the diagonals of a magic square...
There are only magic squares in test cases, however the problem doesn't specify a type of the matrix.
You should definitely strengthen the test suite. Lots of solutions rely on both diagonals being the same, even though this is not a property of the stated problem.
The "antidiagonal" is cooler sounding than "second diagonal"
I learned about fliplr() in another problem and it is helpful here!
Thanks for the hint
I like you're use of a nested loop here.
The last test suite result should be 14.
yes ı agree
Trickey ONE indeed !!
But you can't rely on x always being a magic square - that's just an accident of the inadequate test suite, isn't it? So although this *looks* like a good solution, it isn't really. I think it's bad practice to take advantage of an inadequate test suite.
it doesn't find the sum of the elements of the second but first diagonal
Sort a list of complex numbers based on far they are from the origin.
Matrix indexing with two vectors of indices
Find out missing number from a vector of 9 elements
Determine the number of odd integers in a vector
kmph to mps
Omit columns averages from a matrix
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office