input -> matrix (n*m) with at least one element equal to NaN;
output -> matrix(p*m), the same matrix where we deleted the entire line containing NaN;
Additional test cases have been added.
you can use find function... easy
function y = removeNaN(x)
[n m] = size(x);
for i = 1 : n
maxx = max(isnan(x(i,:)));
if maxx ~= 1
y = (x(i,:))
What is Wrong With THis Code CAn SomeOne Tell ME
It looks like y will return only the last non-NaN row, instead of collecting all of them.
This solution doesn't necessarily work if there are any Inf elements in the matrix. Perhaps it would be best to add a test case where that is the case.
Detect a number and replace with two NaN's
Magic is simple (for beginners)
Find the 9's Complement
Remove from a 2-D matrix all the rows that contain at least one element less than or equal to 4
Matrix which contains the values of an other matrix A at the given locations.
vectorization in N
First non-zero element in each column
Create a matrix X, where each column is a shifted copy of the vector v
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office