According to Google translate, "driemaal is scheepsrecht" means "third time lucky" in Dutch.
I was wondering who would try this one, and how many iterations it would take. :-)
You can also try this solution style with another Cody problem.
Find all elements less than 0 or greater than 10 and replace them with NaN
Reverse Run-Length Encoder
Getting the indices from a vector
Sum the Digits of a Number
frame of the matrix
Wayfinding 3 - passed areas
Create incremental spiral WITHOUT USING EVAL or FEVAL
Robust alignment of coordinate system
Wayfinding 2 - traversing
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