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Nicolas
Nicolas on 21 Jun 2011
Hi,
I'm looking for a way of saving matrices depending on their content.
My loop is generating matrices that I want to save, however sometimes there is no proper values in it (only zeros that i replace by NaN).
I'd like to save only the matrices that have at least one proper value (> 0), but not the ones that have only zeros or NaN.
cheers

Accepted Answer

Matt Fig
Matt Fig on 21 Jun 2011
if ~all(isnan(A(:)))
% Do the saving.
end
But it seems to me that if the only source of nans is from when you replace the zeros with nans, then why not just skip this step and decide to save it based on whether the whole array is not equal to zero?
if any(A(:)) % Array with even one non-zero element passes.
% Do the saving.
end
  1 Comment
Nicolas
Nicolas on 21 Jun 2011
oh yeah, that's better.. didn't know "any" though! thanks

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More Answers (1)

Nicolas
Nicolas on 21 Jun 2011
Actually I found that way
barycenter(barycenter(:,:)==0)=NaN; %replace zeros with NaN
if isnan(barycenter(1:1))<1
Names = sprintf('%s-%d', FileName, N(n));
xlswrite(Names, barycenter)
end
any advices?
  2 Comments
Matt Fig
Matt Fig on 21 Jun 2011
Your method only checks if the first element is nan or not. It looks like you could learn to benefit from linear indexing. For example,
A(A(:)==0) = nan; % Index all elements at once with (:)
Nicolas
Nicolas on 21 Jun 2011
actually if at least a value appears in my matrix, then it has to be in the first cell, that's why I put ..(1,1). thanks for the tip though

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