- Correctly set up the contour plot if your data are truely bound to the shape in fig 2.
- or, use inpolygon to isolate the components of the contour plot that are within the shape in fig 2.

# 2D contour plot considering the boundary of data

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Hi,

I have some discrete data, calling x and y as the coordinates of points and its intensity as of each point as z. I have stored them in 3 vectors namely, testX, testy and testZ. i have tried to make a 2D contour plot by this code:

n=5;

[X,Y] = meshgrid(linspace(min(testX),max(testX),n), linspace(min(testY),max(testY),n));

Z = griddata(testX,testY,testZ,X,Y);

% Plot a graph.

figure

contourf(X,Y,Z,30,'LineColor', 'none');

and the contour I got is shown in figure 1. The problem is the boundray of my data should not be a rectangular as shown in figure 1 and it should be as I plotted in figure 2.

Could you please let me know how to make a contour plot that consider the boundray of data?

Thanks

##### 2 Comments

John D'Errico
on 13 Aug 2021

You have discrete data points. That means there are spaces BETWEEN the data. How does griddata know that the concave hole along one edge is not just another space between data points to interpolate across? Computers cannot read your mind. So when it interpolates across that domain, it just sees a simple rectangle.

The best solution is to use code that will understand the geometry of a non-convex domain, then generating a contour plot on a triangulated region. The problem is, MATLAB does not provide that tool. There are a couple of tricontour tools to be found on the file exchange, but you would need to generate a triangulation of that domain.

A somewhat simpler alternative is to use the triangulation as found, but to then kill off the parts of those contours that fall outside the domain of interest. For this, you need to learn nothing more than how to generate the contours using contourc, and then to use inpolygon (or a polyshape) to zap that which lies outside of the domain.

### Answers (2)

darova
on 15 Aug 2021

Use initmesh to mesh

[x,y,z] = peaks(20);

t = linspace(0,-pi,20);

[xr,yr] = pol2cart(t,2); % round part

x1 = [-3 -3 3 3 xr]; % square coordinates

y1 = [3 -3 -3 3 yr+3]; % square coordinates

gd = [2;length(x1);x1(:);y1(:)]; % geom description of the entire curve

dl = decsg(gd); % decomposition

[p,e,t] = initmesh(dl); % build a mesh

z2 = griddata(x,y,z,p(1,:),p(2,:)); % interpolate Z coord

ff.faces = t(1:3,:)'; % represent each triangle (mesh) as separate face

ff.vertices = p'; % points

ff.facevertexcdata = z2(:); % colors

ff.facecolor = 'interp';

ff.edgecolor = 'none';

patch(ff)

axis equal

##### 0 Comments

Chunru
on 13 Aug 2021

[x, y, z] = peaks(40);

h = pcolor(x, y, z);

h.EdgeColor = 'none';

% Now plot a mask

hold on

ps = polyshape([-1 -1 1 1], [3 2 2 3]); % Specify your shape

plot(ps, 'FaceColor', 'k', 'FaceAlpha', 1);

##### 0 Comments

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