Multiplying matrices with values ​​in polar form

Hello, I'm trying to perform the following operation (Image). I did the operation in complex form in matlab and it worked, but I would like to know how to make it in polar form so I don't need to convert all the values.

a = 1 ∠ 120

I0 = I1 = I2 = 1.7478 ∠ - 90

I was using the following function to multiply complex numbers:

function [ sum ] = pmult( x,y )

A=x(1).*y(1);
B=x(2)+y(2);

sum=[A B];

end

I tried to use it in the matrix, but it was not successful.

Answer 1

[DGM]

It's been a long time since I did this, but here goes:

% note that phasors in polar form are not scalar
% a complex number in rectangular form can be a scalar!
% if you're going to do matrix algebra with the numbers, 
% they really need to be in rectangular form in order to fit
a = [1 120];
I0 = [1.7478 -90];

% define a conversion function, convert to rectangular form
% you could also use pol2cart(), but you'd also need to convert to radians
p2r = @(x) x(1).*cosd(x(2)) + x(1).*sind(x(2))*1j;
a = p2r(a)

a = -0.5000 + 0.8660i

I0 = p2r(I0)

I0 = 0.0000 - 1.7478i

F = [1 1 1; 1 a^2 a; 1 a a^2];
ICC = F*[I0; I0; I0] % answer in rect form

ICC = 
   0.0000 - 5.2434i
   0.0000 - 0.0000i
   0.0000 - 0.0000i

ICCp = [abs(ICC) angle(ICC)/pi*180] % convert to phasor in degrees

ICCp = 3×2

5.2434 -90.0000 0.0000 -90.0000 0.0000 -90.0000

Note that this last conversion only works neatly if ICC is a column vector, since ICCp needs to have twice as many columns as ICC.

[Luccas S.]

nice, thank you very much !