Looping between two functions
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Hi. Please kindly help me solve this problem. the problem really lies from when ghs is mentioned.
function [bhs,ahs,cbs]=btime(t1,t2,t3)
bhs=(t1*t2)+t3;
ahs=t1+t3;
cbs=t2./3;
end
function [abk,kba,t3]=ctime(bhs,cbs)
abk=27.3.*bhs;
kba=bhs+cbs;
t3=35*(abk+kba);
end
wqe=[1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
kli=[51;52;53;54;55;56;57;58;59;60;61;62;63;64;65];
bbc=(21:1:35)';
hsd=size(kli,1);
kas=zeros(hsd,1);
sak=zeros(hsd,1);
cbb=zeros(hsd,1);
abc=zeros(hsd,3);
for i=1:hsd
kas(i)=wqe(i);
sak(i)=kli(i);
cbb(i)=bbc(i);
end
abc(1,:) = [kas(1) sak(1) cbb(1)];
for h=2:1:hsd
abc(h,:)=[kas(h) sak(h) cbb(h)];
end
matrix{1}=abc(1,:);
for i = 2:hsd
matrix{i}=abc(1:i,:);
end
ghs=([]);
for iiv=1:1:hsd
ghs(iiv)=(matrix{1,iiv}(:,:));
t1=ghs(:,1);
t2=ghs(:,2);
t3=ghs(:,3);
[bhs(iiv),ahs(iiv),cbs(iiv)]=btime(t1(iiv),t2(iiv),t3(iiv))
[abk(iiv),kba(iiv)]=ctime(bhs(iiv),cbs(iiv))
end
Final_Answer=[bhs kba]; % The goal is to put each new bhs and cbs under the previous one.
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Answers (1)
Jan
on 30 Jun 2021
Simplify your code:
for i=1:hsd
kas(i)=wqe(i);
sak(i)=kli(i);
cbb(i)=bbc(i);
end
does the same as:
kas = wqe;
sak = kli;
cbb = bbc;
The code:
abc(1,:) = [kas(1) sak(1) cbb(1)];
for h=2:1:hsd
abc(h,:)=[kas(h) sak(h) cbb(h)];
end
does the same as:
abc = [kas, sak, cbb];
The line:
ghs(iiv)=(matrix{1,iiv}(:,:));
is equivalent to:
ghs(iiv) = matrix{1,iiv};
But I do not see, why you create ghs as array at all.
It is not clear, what you want to achieve. With a simplified code this gets clearer, I hope, or if you explain this in detail.
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