Cell array for indexing

Hello

I want to store 38 channels EEG data in a cell array

my code is working with one channel only hoe can i save my 38 cahnnels data in 38 rows of cells array

a=data.signal(:,:); a=a'; % 38 channels EEG signals 
    x=1;
    y=3;
    for  k=1:1:(length(new_positions)/3)
        new_signal{k}=a(new_positions(x):new_positions(y),1) % new_position is indexing matrix
    x=x+3;
    y=y+3;
    end

its only returing 86x1 cell array instead i need 86x38 cell array

Answer 1

[Mathieu NOE]

hello

your assigning a vector to new_signal{k}

so I believe your intention was :

new_signal{k}=a(new_positions(x):new_positions(y),:) % new_position is indexing matrix

% and not 
% new_signal{k}=a(new_positions(x):new_positions(y),1) % new_position is indexing matrix

[hajrah Sultan]

but still its not moving to the next EEG channel data after doing indexing of 1st channel it stops and gives error

Index exceeds the number of array elements

[Mathieu NOE]

Could you share some data so I can better test the code ?

[hajrah Sultan]

its a 7975145x38 matrix after testing 7975145 samples from 1st channel my code need to move to next channel but its not moving to next channel instead it is giving error about dimentions of arry

can you plewase guid me how my code with acces data of all remaning channels

new_signal{k}=a(new_positions(x):new_positions(y),:)

i am passing signal from this condition

here

new_signal is supossed to b 86x38 dimentional cell matrix

a is my raw data of 38 channels 7975145x38

new_position contaions the sapmle no from where it need to pick up sample.

[Mathieu NOE]

can you show was is exactly the error message ??