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Radians to RPM with diff(..) function

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Hi...
I need to finde the RPM from a vector of radians and a vector of seconds (time).
I can do this manually by doing this:
rpmArray = (radiansArray/(2*pi));
minutesArray = timeArray/60;
slopeArray = [];
for counter = 1:length(minutesArray)
if counter < length(minutesArray)
x1 = minutesArray(counter);
x2 = minutesArray(counter + 1);
y1 = rpmArray(counter);
y2 = rpmArray(counter + 1);
slopeArray(counter) = (y2-y1)/(x2-x1);
end
end
slopeArray(end + 1) = slopeArray(end); % Fill in the missing entry
I can not figure out how to do this the "smart way" by using Matlabs diff().
Can anyone help me?
  3 Comments
Kenneth Metzsch
Kenneth Metzsch on 21 Jun 2021
I think it gives me the same problem as diff().
It assumes spacing is 1.
Can you give me an example of how to overcome this?
Stephen23
Stephen23 on 21 Jun 2021
"It assumes spacing is 1."
Did you look at the h/hx/hy inputs?

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Accepted Answer

Chunru
Chunru on 21 Jun 2021
rpmArray = (radiansArray/(2*pi));
minutesArray = timeArray/60;
slopeArray = gradient(rpmArray)./gradient(minuteArray);
  1 Comment
Kenneth Metzsch
Kenneth Metzsch on 21 Jun 2021
Thank you...it works
Actually it wil also work with diff() like this
rpmArray = (radiansArray/(2*pi));
minutesArray = timeArray/60;
slopeArray = diff(rpmArray)./diff(minutesArray);
slopeArray(end + 1) = slopeArray(end);

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