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Removing part of a cell array

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Hello.
I have a data table 1441x1 reading as a cell. The data in this cell is "06/15/2021 12:00 AM" and changes in time by the minute to make up the 1441x1 cell.
My goal is to be left with an array of only the times, as such "12:00" "12:01"... and so on. Any help is appreciated.

Accepted Answer

Walter Roberson
Walter Roberson on 16 Jun 2021
Why not just convert as-is ?
S = '06/15/2021 12:00 AM'
S = '06/15/2021 12:00 AM'
datetime(S, 'InputFormat', 'MM/dd/yyyy hh:mm a', 'Format', 'yyyy/MM/DD HH:mm')
ans = datetime
2021/06/166 00:00
Note the InputFormat uses hh, which is the code for 12-hour numbering format. The 'a' field accepts AM or PM and informs MATLAB of which 12 hour block.
The OutputFormat I coded to use HH which is the code for 24-hour numbering format.
  3 Comments
Brian Gregory
Brian Gregory on 16 Jun 2021
Actually, I was able to get this to work using the different format yyyy-MM-dd which is the one I desired. Thanks!
Walter Roberson
Walter Roberson on 16 Jun 2021
opps yes DD should have been dd

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