find the variance of autocorrelation function

i want to find the sum of the below.but i am getting an error.please help me. i write the program in two ways.both are same.but both getting different answer

for i=1:20 s(i)=(2*(acf(i+1)^2)); s1=sum(s(i)); end

AND for k=1:20 s=0; for j=1:k s=s+2*acf(j+1)^2; end end

gives different answer.what is the error in this programs? both are same

Answer 1

[Jaynik]

Hi Chithralekha,

The two pieces of code are not equivalent, and that is why they are producing different results. In first piece of code, the value of s(i) is being calculated for each i from 1 to 20, and then summed up the current value of s(i) in each iteration. This means s1 will only hold the value of the last element s(20) because it is being overwritten in each iteration.

In the second piece of code, s is initialized to 0 at each iteration of k, then sum is calculated for the value of 2 * acf(j+1)^2 from j=1 to j=k. The final value of s will be the sum of all these values up to k=20.

Hope this helps!