Arithmetical mean above max
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Is it possible that, due to precision matter, arithmetical mean of an array is above max of same array ?
Is Matlab then limiting mean to min-max interval (at least for display) ?
Regards Claire
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Answers (3)
David Sanchez
on 16 Aug 2013
The mean value ( either geometric or arithmetic ) of an array can never be above the maximum value of the array. Matlab does not have to limit the result of the operation.
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Claire
on 16 Aug 2013
1 Comment
David Sanchez
on 16 Aug 2013
I don't know of any case. However, if dealing with very small numbers, the result will be prone to some error. In any case, achieving an average of a set above the maximum value of that set, (beside being against its definition) is extremely unlikely even when working with very small numbers.
Jan
on 17 Aug 2013
Edited: Jan
on 17 Aug 2013
Matlab's mean(x) uses the calculation sum(x) / numel(x). Therefore it suffers from the numerical instabilities of sum:
x = [1e17, 1, -1e17]
sum(x)
This replies 0 instead of 1, because the limited floating point precision does not allow to distinguish 1e17 and 1e17+1. This means, that in sum() small values can vanish, when they are surrounded by large numbers with different sign, and of course this matters partial sums also. But this cannot lead to the situation, that the sum is larger than numel(x)*max(x), except if you reach the overflow such that sum() replies Inf. Then sum(x)/n differs from sum(x/n).
v = [realmax, realmax]
mean(v)
(What does this reply? I cannot check this currently.)
So perhaps this would be a better implementation of MEAN:
function m = meanX(x)
m = sum(x) / numel(x);
if ~isfinite(m)
m = sum(x / numel(x));
end
A furter effect appears for large arrays, when Matlab distributes the partial sums to different threads. Then the floating point effects depend on the number of cores also, but here the sum cannot exceed numel(x)*max(x) also, except for the above mentioned exception.
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