**Similar to the Grouped-Z Project function in ImageJ where you can do Standard Deviation of your data with a group size of 10.
3-Dimensional Matrix and Standard Deviation
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Sami Case
on 23 May 2021
Commented: Sami Case
on 25 May 2021
Hi there,
I have a 3-Dimensional matrix (sizeX, sizeY, 700 Frames). I would like to group the "frames" in groups of 10, so that I can take the standard deviation of each of these groups of frames. E.g. -- Since I have 700 frames (z values), I would like to take the standard deviation of 1:10, then 11:20, then 21:30. For mean, I could just bin them in groups of ten (using for loop and mean function) and get my 70 values. But for standard deviation, I'm not sure how to do this.
Accepted Answer
Sulaymon Eshkabilov
on 23 May 2021
Hi,
Here is a relatively simple solution for the standard deviation calculation:
D = DATA; % DATA of size: X-by-Y-Zs, where Zs = 1:700;
IND = 1:10:700;
for ii=2:numel(IND)
S_D(ii-1) = std2(D(:,:,IND(ii-1):IND(ii))); % Standard deviation
M_D(ii-1)=mean2(D(:,:, IND(ii-1):IND(ii))); % Mean values
end
Good luck.
4 Comments
DGM
on 24 May 2021
Edited: DGM
on 24 May 2021
Try this:
D = rand(10,10,100); % random sample data
blocksize = 10; % how many pages to collapse?
npages = size(D,3);
IND = 1:blocksize:npages;
stdpict = zeros(size(D,1),size(D,2),numel(IND));
meanpict = zeros(size(D,1),size(D,2),numel(IND));
for ii=1:numel(IND)
idxrange = IND(ii):(IND(ii)+blocksize-1);
% Standard deviation of block along dim 3
stdpict(:,:,ii) = std(D(:,:,idxrange),0,3);
% Mean of block along dim 3
meanpict(:,:,ii) = sum(D(:,:,idxrange),3)/blocksize;
end
% the indexing will break if npages is not integer-divisible by blocksize
This does operations along dim3 of each block of pages. That sounds like what you're after.
Prior code was also indexing 1:11, 11:21, 21:31, etc, and dropping the last sample block.
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