after applying a filter -i design- to a real signal, it returns complex signal after ifft
3 views (last 30 days)
Show older comments
Hamza AKYILDIZ
on 14 May 2021
Answered: Paul Hoffrichter
on 14 May 2021
[x,fs]=audioread('some.wav');
n=length(x);
t = ((0:n-1)*(fs/n));
y=fft(x);
f = ((0:n-1)*(fs/n));
y0 = fftshift(y);
f0 = ((-n/2:n/2-1)*(fs/n));
noise = find(abs(y0) == max(abs(y0)));
noiseW= [2*pi*f0(noise(1)) 2*pi*f0(noise(2))];
z1=exp(1i*noiseW(1));
z2=exp(1i*noiseW(2));
z=exp(1i*2*pi*f0);
H=(1-z1*(z.^-1)).*(1-z2*(z.^-1));
out0=y0.*(H.');
out=ifftshift(out0);
signal=ifft(out);
audiowrite('output.wav',final,fs);
2 Comments
Daniel Pollard
on 14 May 2021
I'm not sure I understand the problem. The FFT (and the IFFT) produce complex outputs by their definition. Could you give some more details? What were you expecting to happen?
Accepted Answer
Paul Hoffrichter
on 14 May 2021
Your imaginary part only is non-zero due to the usual floating point roundoffs and truncations. Fix this using round:
signal=ifft(out);
signalRound = round(signal, 10);
0 Comments
More Answers (0)
See Also
Categories
Find more on Multirate Signal Processing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!