Questions about bvp4c solution
Show older comments
Hi, I solved correctly a system of ODE second order with BCs, with the instruction bvp4c.
However, I have some questions about it.
My code is as follows:
...
xmesh = linspace(1e-5,1.5*1e-3,20);
solinit = bvpinit(xmesh,1e-3*[0,0,0,0,1,1,1,1]);
sol = bvp4c(@bvpfcn,@bcs,solinit);
plot(sol.x,sol.y)
1) When I plot the solution, I should choose in x interval sol.x or xmesh? What is their difference?
2) I don't understand how Matlab uses the second vector [0,0,0,0,1,1,1,1] in bvpinit.
It should represent the initial guess of solution (I have 8 variables), but it seems that its values don't change final solution. Is it right?
I've already read Matlab guide about bvp4c, but I have not found these answers.
Thank you!
Accepted Answer
More Answers (0)
Categories
Find more on Boundary Value Problems in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!