Elements of matrix after an equation

Hi! Previosuly i got help from here with this code:

A2 = zeros(size(A,1),1);
iA2 = 0;

for iA = 1:size(A,1) 
    num = A(iA,1) * A(iA, 2);
    if num < 0        
        iA2 = iA2 +1;
        A2(iA2) = num;        
    end
end
A2 = A2(A2 < 0)

which creates a matrix with elements that are only negative. Now further i have this line:

Pmax = max(abs(A2))

Which takes out the single maximum value from A2. Now the question is can i bring out the matrix elements that value?

In short i need A(iA,1) and A(iA, 2) from Pmax = max(abs(A2))

[Stefan Juhanson]

Other solutions to the first part were:

A2 = A(:, 1) .* A(:, 2);

A2 = A2(A2 < 0);

or

index = (A(:, 1) < 0) ~= (A(:, 2) < 0);

A2 = A(index, 1) .* A(index, 2)

Basically i need A(index, 1) and A(index, 2) while abs(A(index, 1) .* A(index, 2)) = max

If this helps to give a solution to my problem of finding those elements.

Answer 1

[Matt J]

p = A(:, 1) .* A(:, 2);

index=(abs(p)==norm(p,inf)) & p<0;

a1=A(index,1);
a2=A(index,2);