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Define function for a transfer function

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Vinit Dighe
Vinit Dighe on 21 Apr 2021
Answered: Divija Aleti on 26 Apr 2021
I have a transfer function given by: .
s = tf('s');
sys_closed = 8/(1*s^3+2*s^2+10*s+8);
t = linspace(0,10,400);
y = step(sys_closed,t);
plot(t,y)
Then, for the above transfer function, my coefficients are: a = 1, b = 2, c = 10 and d = 8. I would like to define a function, which returns the values of y for different values of coefficients. To this aim, I defined a function file (named uq_dynamic):
function V = uq_dynamic(X)
a = X(1);
b = X(2);
c = X(3);
d = X(4);
s = tf('s');
sys_closed = d./((a.*(s.^3))+(b.*(s.^2))+(c.*s)+d);
t = linspace(0,10,400);
y = step(sys_closed,t);
V = y;
My main working file requires me to define the transfer function (line 7) in vector notation (since I am coupling Matlab to a third-party toolbox: UQLab). I believe the syntax is incorrect, which returns an error. Could someone please help me to rectify the above transfer function in vector notation/correct syntax. Thank you.
Best,
Vinit
  1 Comment
Paul
Paul on 23 Apr 2021
What does "vector notation" mean?

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Answers (1)

Divija Aleti
Divija Aleti on 26 Apr 2021
Hi Vinit,
From my understanding, 'X' is a vector containing 'a', 'b', 'c', 'd' which are scalars. As these are scalars, you do not need to use the dot operator('.') while performing arithmetic operations. Have a look at the following example code where the function is called with X = [1,2,10,8] as the input:
X = [1,2,10,8];
uq_dynamic(X);
function V = uq_dynamic(X)
a = X(1);
b = X(2);
c = X(3);
d = X(4);
s = tf('s');
sys_closed = d/((a*(s^3))+(b*(s^2))+(c*s)+d); %This is the line which differs from your code
t = linspace(0,10,400);
y = step(sys_closed,t);
V = y;
end
This function returns the values of 'y', for different values of 'X'.
Hope this helps!
Regards,
Divija

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