how can compute the log10 of the image ? what is the effect of this operation ?
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how can compute logarithm of base 10 for the image ? what is the effect of this operation ?
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Accepted Answer
Iain
on 21 Jun 2013
It suppresses small changes on large values and highlights changes of smaller values.
1 becomes 0, 10 becomes 1, 100 becomes 2...
im = log10(image);
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