How to change a portion of cell array?

I have a large data set where I've put trials into a cell array. So each cell contains 1 trial and within that cell trial{1,1} there is specific information about the trial. The first column in trial{1,1} is time.

How do you access the first column for each cell?

In the end, I want to change the first column to have time start from 0. So I plan on doing time = time-1

Answer 1

[Star Strider]

Guessing as to what the structure is, try this:

trial{1} = {(1:10).', rand(10,1), 'Information'};
FirstColumn = trial{1}{:,1}
SecondColumn = trial{1}{:,2}
ThirdElement = trial{1}{3}

producing (in this random run):

FirstColumn =
     1
     2
     3
     4
     5
     6
     7
     8
     9
    10

SecondColumn =
      0.76396
       0.8182
      0.10022
      0.17812
      0.35963
     0.056705
      0.52189
      0.33585
      0.17567
      0.20895

ThirdElement =
    'Information'

.

[Mirthand]

My variable is a 79x1 cell

and then when I go into that variable, lets call it variable x

there are subarrays that are different sizes (y) but consistent in column (y, 7) double.

it's stimilar to your random generation of trial except that instead of a 1 x 1 cell, its a 79 x 1 cell that contains doubles instead of cells.

[Star Strider]

If you want help specifically with your data, post (upload) the data. Preferably, first save it as a .mat file.

[Mirthand]

Thank you! I've attached it here.

[Star Strider]

They all contain double arrays, so the addressing is straightforward.

To get Column 7 from each element in ‘trials’:

D = load('trials.mat');
trials = D.trials;
T01_C7 = trials{1}(:,7);                            % ‘trials’  #1, Column #7
T79_C7 = trials{79}(:,7);                           % ‘trials’ #79, Column #7

I just did it for the first and last cells here, however the rest would be straightforward. These only contain double arrays, not other information, so I assume those are in a different cell array.

[Mirthand]

Thank you!

[Star Strider]

As always, my pleasure!