Converting an n x m matrix into a single array

I have the following

source = [8202, 8202, 8202, 8201, 8202, 8202, 8202, 8208];

I want to have an array containing the binary values of source but as a single array,

Array = ( de2bi(8202) de2bi(8202) .... de2bi(8206))

so that I can index the resultant bits of the eight entries one by one,

I am essentially trying to obtain a complete bit stream of source data in one array so that I can work with the individual bits

In this case I am expecting an array with 8 * ceil(log2(max(source)))

Kindly assist,

Answer 1

[DGM]

How about something like this?

source = [8202, 8202, 8202, 8201, 8202, 8202, 8202, 8208];

sbin=de2bi(source,'left-msb'); % pick which bit order you need
bitstream=reshape(sbin',[1 numel(sbin)]) % reshape into a vector