How to apply the loop index on the output (filename) of the sprintf function?

The program gives the following output variables in the workspace as shown in figure. I have three questions regarding the output. 1) The loop index runs from n=4:1:6; but the output value of n is only 6. How can I convert n as a array matrix i.e [4 5 6]?. 2) The value of the filename shows only depout_6.mat perhaps n runs three times 4,5,6. I want the output filename according to the sequence of index n, i.e depout_4.mat, depout_5.mat, depout_6.mat. 3) The command window displays the results, dep_rat three times with increasing rows as shown in the second figure. I just want the last one to display with three rows. How can I resolve these issues?

clc;
clear all;
%------------------------------Program-------------------------------------
load EC.mat
for n =4:1:6;
    filename = sprintf('depout_%d.mat',n);
    data_out=load(filename,'dep');%dep is the variable in the filename(oute- FOV data in this case)
    dep_out(n-3,:)=data_out.dep(n,:);
    filename2 = sprintf('depinn_%d.mat',n);
    data_inn=load(filename2,'dep');%dep is the variable in the filename(inner-FOV data in this case)
    dep_in(n-3,:)=data_inn.dep(n,:);
    dep_rat(n-3,:)=[dep_out(n-3,:)./dep_in(n-3,:)]% this is the depolarisaation_rat parameter in the paper. the value,...
    %is greater than one because we calculated dep_rat=dep_out/dep_in. Calculating dep_rat=dep_in/dep_out will give you
    %value less than  one
end

[KSSV]

1) The loop index runs from n=4:1:6; but the output value of n is only 6.

It is becuase, the loop index will be overwritten, you will see the value of n which will be the last index i.e. 6.

2) The value of the filename shows only depout_6.mat perhaps n runs three times 4,5,6.

It is because, you are overwrititng the filename in a loop and you will be seeing the last value.

[Wiqas Ahmad]

1) Is it possible to see n as a row matrix i,e [4 5 6]? If so, how? 2) I also want to see filename depout_4.mat, depout_5.mat and depout_6.mat if posiible?

[Rik]

You can make n a vector, but that is probably not what you want if you want to use a for loop.

Why do you want to see those file names as well? Your code handles them inside the loop already?

I'm starting to suspect that this is not your code. If you have trouble with Matlab basics you may consider doing the Onramp tutorial (which is provided for free by Mathworks).

[Wiqas Ahmad]

Actuall the first row in the output dep_rat is related to 4, then 5 and the last is 6. I want to justify my output with showing these files.

Answer 1

[Bjorn Gustavsson]

In your "workspace" panel you see the values (sizes) of the variables as they are after completing the loop. Your filname-variables have been depout_4.mat etc in previous iterations through the loop. You should be able to confirm this if you change the loop to this:

% clc;
% clear all; 
%------------------------------Program-------------------------------------
load EC.mat
for n =4:1:6;
    filename = sprintf('depout_%d.mat',n);
    fprintf('n: %d, filename: %s\n',n,filename)
    data_out=load(filename,'dep');%dep is the variable in the filename(oute- FOV data in this case)
    dep_out(n-3,:)=data_out.dep(n,:);
    filename2 = sprintf('depinn_%d.mat',n);
    fprintf('n: %d, filename2: %s\n',n,filename2)
    data_inn=load(filename2,'dep');%dep is the variable in the filename(inner-FOV data in this case)
    dep_in(n-3,:)=data_inn.dep(n,:);
    dep_rat(n-3,:)=[dep_out(n-3,:)./dep_in(n-3,:)]% this is the depolarisaation_rat parameter in the paper. the value,...
    %is greater than one because we calculated dep_rat=dep_out/dep_in. Calculating dep_rat=dep_in/dep_out will give you
    %value less than  one
    disp('push any key to continue (after looking at the workspace-panel...)')
    pause
end

HTH