How to use two conditions in a same loop?

How to use two conditions in a single loop? for example i wnat to check the any value of x (cloumn) if it is less than 1, the code shall run iteration till any value reaches to 1. when any one value of x cloumn reaches to 1, the code shall proceed to the next row and repeat the same for this row, and run the code till the last column has the one value reaches to 1. here I am posting my code. Please help. Thanks in advance

i = 1:n-1

x=0;

while x<1

itn=itn+1

Rhn(1:n,i) = ((pi*rh(1:n,i).^4)/8*nuD*L).*[1./(x+(1-x)*M)];

qhn(1:n,i)=qh(1:n,i).*Rh(1:n,i)./Rhn(1:n,i);

Vh(1:n,i) = (qhn(1:n,i))./Ah(1:n,i);

if x<=0.5

delXmax = 0.1

else

delXmax = 0.07

end

deltat=min(min(delXmax./Vh(1:n,i)))

x= x+Vh(1:n,i)*deltat;

if x>=1

i = i+1

end

end

end

Answer 1

[ag]

Hi Irfan,

I understand that you want to iterate over columns of a matrix, checking each column's values to see any value of x is less than 1. And that once a value in the current column reaches 1, the iteration should move to the next column and repeat the process until all columns have been processed.

The below code outlines how you can structure the required logic:

% Assuming n and other utilized functions are pre-defined
itn = 1;
for i = 1:n-1
    x = 0;  % Initialize x for each column
    while any(x < 1)  % Check if any value of x is less than 1
        itn = itn + 1; 

        % Update Rhn, qhn, and Vh based on provided code
        Rhn(1:n, i) = ((pi * rh(1:n, i).^4) / (8 * nuD * L)) .* (1 ./ (x + (1 - x) * M));
        qhn(1:n, i) = qh(1:n, i) .* Rh(1:n, i) ./ Rhn(1:n, i);
        Vh(1:n, i) = qhn(1:n, i) ./ Ah(1:n, i);

        % Determine delXmax based on the value of x
        if any(x <= 0.5)
            delXmax = 0.1;
        else
            delXmax = 0.07;
        end

        % Calculate deltat and update x
        deltat = min(min(delXmax ./ Vh(1:n, i)));
        x = x + Vh(1:n, i) * deltat;
        
        if any(x >= 1)
            break;  %move to the next column
        end
    end
end

Hope this helps!