MATLAB Answers

Invalid use of operator...it is saying it has a problem with '&&' in line 52

26 views (last 30 days)
Donny Flynn
Donny Flynn on 25 Feb 2021
Edited: Donny Flynn on 25 Feb 2021
clc
%%====== Setup =========
S = [[3000 1000 2000];[1000 1000 4000];[2000 500 3000]];
sol = [];
c = S(:,4);
B = S; B(:,4) = [];
[sr sc] = size(B);
Axes = eye(sc);
%% ============ Find Interceptions ===============
A = [B(1,:);B(2,:)];
b = [c(1);c(2)];
sol = [sol linsolve(A,b)];
A = [B(1,:);B(3,:)];
b =[c(1);c(3)];
sol = [sol linsolve(A,b)];
A = [B(2,:);B(3,:)];
b = [c(2);c(3)];
sol = [sol linsolve(A,b)];
%% === Check for axes intersections ==
for i=1:sc
for j=1:sr
A = [Axes(i,:);B(j,:)];
b = [0;c(j)];
sol = [sol linsolve(A,b)];
end
end
%% === Find corner points of feasible
%% === region ======
[r c] = size(sol);
feasible = []; tolerance = 0;
for i=1:c
v = (sol(:,i));
x = v(1); y = v(2); z = v(3);
if (3000*x + 1000*y + 2000*z) <= 24000 + tolerance
&& (1000*x + 1000*y + 4000*z) <= 16000 + tolerance &&
(2000*x + 500*y + 3000*z) <= 48800 + tolerance
feasible = [feasible sol(:,i)];
end
end
disp(feasible)
%% ====== Find optimum =======
  2 Comments
Donny Flynn
Donny Flynn on 25 Feb 2021
Yes I noticed that, i changed it to 3. Thank you.
What were the other issus?

Sign in to comment.

Accepted Answer

David Hill
David Hill on 25 Feb 2021
To continue the line of code you need three dots ...
if (3000*x + 1000*y + 2000*z) <= 24000 + tolerance ...
&& (1000*x + 1000*y + 4000*z) <= 16000 + tolerance &&...
(2000*x + 500*y + 3000*z) <= 48800 + tolerance
feasible = [feasible sol(:,i)];
end
  1 Comment
Donny Flynn
Donny Flynn on 25 Feb 2021
Thank you I am not too familair with MATLAB...learning the syntax, I appreciate it.

Sign in to comment.

More Answers (0)

Tags

Products


Release

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!