norm of vector with cosine(var)

How can I calculate the norm of a vector which is of form [sin(t);cos(t)]?
I tried
f=x*y^2;gamma=[2*cos(t);sin(t)];tmin=0;tmax=2*pi;
mod=matlabFunction(norm(dgamma))
value=int((fgamma)*mod,t,tmin,tmax)
with answer
mod =
function_handle with value:
@(t)sqrt(abs(cos(t)).^2+abs(sin(t)).^2.*4.0)
value = int(2*cos(t)*sin(t)^2*(abs(cos(t))^2 + 4*abs(sin(t))^2)^(1/2), t, 0, 2*pi)

3 Comments

John D'Errico
John D'Errico on 21 Feb 2021
Edited: John D'Errico on 21 Feb 2021
The norm of that vector thus [sin(t),cos(t)]? It is 1.
Why do you need to calculate the number 1? If you want though, you might try 2/2. :)
That was an example @John D'Errico...
It's an unknown function handle put in by the user but my function had issues with calculating the euclidian Norm of a vector when theres cosine or sine in it, that's why I used the example.
I solved it by a simple workaround:
mod=0;
for k=1:nargin(f)
mod=mod+dgamma(k)^2;
end
mod=sqrt(mod);
integr=sym((fgamma)*mod)
value=int(integr,tmin,tmax)
John D'Errico
John D'Errico on 21 Feb 2021
Edited: John D'Errico on 21 Feb 2021
Ok, so you have a more complex vector. I would note that what you claim you tried is meaningless, because it uses undefined variables, etc.
What is wrong with norm(V)?
And if that does not work, then what is wrong with sqrt(sum(V.^2))?
If you say you had problems, then you need to say WHAT problems, because what I've written does what you are asking. AND, you need to show code that actually does what you claim you tried.

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