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Need help with creating a half/full bridge rectifier output

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David Carrel
David Carrel on 3 Feb 2021
The code is as follows,
clc
clear all
i=1;
for t=0:1e-3:0.2
x(i)=t;
y(i)=10*sin(2*pi*100*x(i));
i=i+1;
end
plot(x,y)
I am tasked with adding an if/else statment on the inside of the for loop to create a half and full bridge rectified signal.
Can anyone help me please?

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