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How can I keep asking the user for correct input even after they press enter?

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JkBlack
JkBlack on 29 Jan 2021
Edited: JkBlack on 2 Feb 2021
Hello,
I want my statement to continue to be prompted until correct input is given.
Prompt the user to write "ready" or "Ready" and keep prompting the user until they do so, and if they just pressed enter, a statement shows up asking them to "Please type "Ready"". I am a little lost as to how to do that using while(1) loop. I have this so far...
while (1)
Ready= input('When you are ready to play please type "Ready": ','s');
if Ready== 'ready' | Ready== 'Ready'
break
end
end
Please help
Thank you in advance.

Accepted Answer

Adam Danz
Adam Danz on 29 Jan 2021
Edited: Adam Danz on 29 Jan 2021
Most of the time case sensitivity shouldn't be a constraint in these types of queries. The demo below accepts any form of "ready" (READY, ready, Ready, reaDY, etc).
response = '';
while ~strcmpi(response,'ready')
response = input('When you are ready to play please type "Ready": ','s');
end
If you truly only want to accept Ready and ready, use this condition instead,
while ~any(strcmp(response, {'Ready','ready'}))
Another form that gives the user feedback on their error,
instructions = 'When you are ready to play please type "Ready": ';
baseInstructions = instructions;
response = '';
while ~strcmpi(response,'ready')
response = input(instructions,'s');
instructions = sprintf('%s, (you typed "%s") ',baseInstructions, response);
end
Another idea since this is a binary task (the user types the correct word or they do not), why not use a question or message box?
qdh = questdlg('When you are ready to play, please press go!', 'Game', 'Go!','Go!');
You could also add a "Cancel" option.
  5 Comments
JkBlack
JkBlack on 2 Feb 2021
Your help is very much appreciated! Thank you for pointing this out and sharing this information, will keep it in my mind.
Best Regards,
Jk

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More Answers (1)

per isakson
per isakson on 29 Jan 2021
Use
strcmpi( Ready, 'ready' )
instead of
Ready== 'ready' | Ready== 'Ready'
Don't use == in combination with character arrays to compare words. It compares character by character.
>> 'abc'=='a*c'
ans =
1×3 logical array
1 0 1
in contrary to strings
>> "abc"=="a*c"
ans =
logical
0
  2 Comments
JkBlack
JkBlack on 29 Jan 2021
Yes this worked! Thank you very much for sharing this information!
Best Regards,
JK

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