# how to change the number that decreases in the array element to the same number, for example 0 (zero)

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Naufal Arfani on 19 Jan 2021
Commented: Naufal Arfani on 20 Jan 2021
hello everyone,
I have an array element value as in the following code and this number will keep decreasing to about 10e-6, there should be a lot up to (1x500) but I just gave a few examples with this,
is there an easy way to change it to the same number eg 0 (zero)?
So in general it is not if it is worth below 1, for example, then it is zero, not like that, but if it is worth decreasing
Thank you very much
a = [100.001469926008 0.0140073495254864 0.00452326089811489 0.00228582409151486 0.00157249586126199 0.00121055360392781 0.000988328854777707 0.000836846113296335 0.000726496714817108]
if %there are array elements that are keep decreasing
%then everything changes to 0 so it remains (1x500) but everything is 0
end

per isakson on 19 Jan 2021
Edited: per isakson on 19 Jan 2021
Is something like this what you are asking for?
%%
a = [100.001469926008 0.0140073495254864 0.00452326089811489 ...
, 0.00228582409151486 0.00157249586126199 0.00121055360392781 ...
, 0.000988328854777707 0.000836846113296335 0.000726496714817108 ];
%%
daff = diff(a);
ix = find( a<1, 1, 'first' ); % "worth below 1"
if all( daff(ix:end) < 0 ) % "keep decreasing"
a(ix:end)=0; % "changes to 0"
end
it returns
>> a
a =
Columns 1 through 5
100 0 0 0 0
Columns 6 through 9
0 0 0 0
%%
daff = diff(a);
if all( daff < 0 ) % "keep decreasing" monotonically decreasing
a(:) = 0; % "changes to 0" "(:)" is needed to replace ALL values by 0
end
Naufal Arfani on 20 Jan 2021
okay, thank you very much for all the help. I'm sorry for always asking and troubling you @per isakson

R2019b

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