MATLAB Simulation for Calculation of Series and Parallel Capacitor

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NUR HAFIZAH
NUR HAFIZAH on 4 Jan 2021
Answered: Rishabh Mishra on 7 Jan 2021
here is my coding to calculate the capacitance of series and parallel capacitor. but, matlab not regonize the part of calculate the D and W on the coding. I wish anyone can help me to find out the errors found in this coding. Thank you
%%Simulation of Capacitance of Two Type of Capacitor
%The value of the dielectric, ε_r surface area, S and its
%dimension (w,d) will be ask during the start of the program code.
clear
clc
% Constant
eps0 = 8.854187817e-12;
% Ask User Input
%dielectric
%Er1 and Er2
prompt = 'Insert the value of dielectric,Er1';
Er1 = input(prompt)
prompt = 'Insert the value of dielectric,Er2';
Er2 = input(prompt)
%Calculation of Er1 and ER2 for series capacitor
disp('The Calculation of Er1 and ER2 for series capacitor');
Y = (Er1*Er2)/(Er1+Er2)
%Calculation of Er1 and ER2 for series capacitor
disp('The Calculation of Er1 and ER2 for parallel capacitor');
X = Er1+Er2
%insert S,d and w
disp('S = surface area');
disp ('d = dimension for series capacitor');
disp('w = dimension for parallel capacitor/n');
prompt = 'Insert the value of S';
S = input(prompt)
prompt = 'Insert the value of d';
d = input(prompt)
prompt = 'Insert the value of w';
w = input(prompt)
%calculation of capacitance for series capacitor
disp('The Calculation of Capacitance for Series Capacitor');
disp('C =((2*eps0*S)/d)*((Er1*Er2)/(Er1+Er2))');
disp('The answer is:\n');
C1 = (2*eps0*S)/d
%calculation of capacitance for parallel capacitor
disp('The Calculation of Capacitance for Parallel Capacitor');
disp('C =((eps0*S)/2w)*((Er1+Er2))');
disp('The answer is:');
C2 = (eps0*S)/(2*w)

Answers (1)

Rishabh Mishra
Rishabh Mishra on 7 Jan 2021
Hi,
I tried reproducing the code you provided on my system and it is working without errors. You’ve mentioned that you are calculating the values ‘D’ & ‘W’. However, in the code, user is prompted to input the values ‘d’ & ‘w’. Please clarify on this aspect.
Below I have provided the code to solve this issue:
% define dielectric constant
eps0 = 8.854187817e-12;
% declare variables Er1 Er2 using symbolic math
syms Er1 Er2;
% declare variables s, d, w using symbolic math
syms S d w;
% Net Dielectric of Parallel combination
Y = (Er1*Er2)/(Er1+Er2);
% Net Dielectric of Series combination
X = Er1+Er2;
% Net Capacitance in Parallel combination
C2 = (eps0*X*S)/w;
% Net Capacitance in Series combination
C1 = (eps0*Y*S)/d;
% take inputs for Er1, Er2, S, D & W
Er1in = input('Enter value of Er1: ');
Er2in = input('Enter value of Er2: ');
Sin = input('Enter value of S: ');
Din = input('Enter value of D: ');
Win = input('Enter value of W: ');
% evaluate the series & parallel resistances
disp(subs(C1,[Er1 Er2 S d w],[Er1in Er2in Sin Din Win]));
disp(subs(C2,[Er1 Er2 S d w],[Er1in Er2in Sin Din Win]));
In the code above, I have used syms to declare symbolic variables. Function ‘subs’ is used to substitute the values of variables ‘Er1’, ‘Er2’, ‘S’, ‘d’, ‘w’ (obtained from the user) into expressions of ‘C1’ & ‘C2’.
Hope this helps.

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