matrix manupulation and reading diagonally
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Hello Team,
i have a matrix
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16];
I want to read the matrix in the order mentioned in the matrix.
Starting from left bottom (1), then right top (2) and then again 2nd diagonal from left (3,4) and then 2nd right diagonal (5,6) and so on and so forth.
Please support in resolving it.
Edit : i there any way to create this kind of matrix for any n-by-n matrix automatically. i have created this Matrix_test manually but if i want 8x8 matrix in similar pattern . How to create it through generic code.
Thanks in advance.
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Accepted Answer
Stephan
on 8 Dec 2020
This function may help:
M = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
MyResult = readDiag(M)
function R = readDiag(M)
R = cell(2,numel(diag(M)));
for k = 1:numel(diag(M))-1
R{1,k} = diag(M,-numel(diag(M))+k);
R{2,k} = diag(M,numel(diag(M))-k);
end
R = reshape(R,[],1);
R = [R; {diag(M)}];
R = cell2mat(R);
end
result is:
M =
13 10 5 2
7 14 11 6
3 8 15 12
1 4 9 16
MyResult =
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
More Answers (1)
Bruno Luong
on 8 Dec 2020
Edited: Bruno Luong
on 8 Dec 2020
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
[m,n]=size(Matrix_test);
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
Matrix_test(is)
4 Comments
Bruno Luong
on 11 Dec 2020
Create matrix with dimension m x n.
m=8; n=8;
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
M=zeros(m,n);
M(is)=1:m*n
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