Code acceleration by mex-file

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Marc Laub
Marc Laub on 2 Dec 2020
Answered: Marc Laub on 3 Dec 2020
Hey,
I'am new to the mex-section, but I wanted to accelerate my code, more a very specific time consuming function.
To start with I wrote a little funtction to see how much faster this function as mex is. The same is done in a tutorial, bot somehow my mex code isn't as fast as the one in the tutorial. So my question is on what exactly does the speed up with mex functions depends on?
function N=addodd(L)
counter=1;
N=0;
while ne(counter,L)
if ne(mod(counter,2),0)
N=N+counter;
else
N=N;
end
counter=counter+1;
end
end
Above is my function, that I run in Matlab as you see it above, and as mex-function.
Here on my Laptop Matlab needs fpr N=10^8 about 9 seconds (same as in the tutorial). My mex function needs about 7 seconds, whereas it needs only 1 second in the tutorial. So what am I doing different?
Its not a function where memory should be the bootleneck. And on my much faster desktop pc I can run the MatLab code for same N in only 4 seconds, mex also needs 4sec here.
Why would my Laptop take the same time for the matlab code, but 7 times longer for the mex code??
Where is the secret?
Maybe somebody coukld help me with this.
Many thanks in advance
Best regards
  2 Comments
Raghu Boggavarapu
Raghu Boggavarapu on 3 Dec 2020
mod(counter,2) is an expensive function when dealing with floating point inputs. Please modify the code as follows to see speed up in MEX execution time :
function N=loopTest(L)
counter=int32(1);
N=int32(0);
while ne(counter,L)
if ne(mod(counter,2),0)
N=N+counter;
else
N=N;
end
counter=counter+int32(1);
end
end
  • Avoid floating point arithmetic where unnecessary to speed up the execution.
  • Additionally turn off "Integrity Checks" and "Responsiveness Checks" in MEX configuration to speed up the execution time.

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Answers (1)

Marc Laub
Marc Laub on 3 Dec 2020
Thanks, it was the double instead of integer problem.
I simply typed the code as in that tutorial but somehow in his tutorial his input und variables where directly interpreted as integers, whereas mine where doubles, even though none of us had declared them as int.

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