How to create a periodic function?

The function at [0,2] is y=x for [0,1] and y=2-x for [1,2], I want the above function repeated at [2,10], so I need a periodic funtion in the whole [0,10], who can help me code it ,thank you.

 Accepted Answer

Not sure what you mean by "repeated at [2,10]". Maybe this:
y = mod(x,2);
ix = y > 1;
y(ix) = 2 - y(ix);

9 Comments

Just like this
Plot what I gave you ...
Thank you, you give me the right code, but I cannot understand the code "y = mod(x,2);", could you please discribe it for me?
In addition, I want to use this one, could you help me revise it
Since you are making a periodic function, the mod(x,2) simply puts all of the input values into the range of one cycle. From there it is just a matter of forming the proper outputs of one cycle. The y=x part for the [0,1] input didn't need any adjustment so no extra code for that. Only the [1,2] part needed the extra code.
For this new function, you simply need to scale the x input properly and then use the same algorithm. E.g.,
y = mod(x/3,2);
ix = y > 1;
y(ix) = 2 - y(ix);
Thank you are right,but where can find the define of “mod”.
In addition, how can I revise the amplitude to 0.2, how can I revise it?
To revise the amplitude, simply add one more line to the algorithm:
y = 0.2 * y;
The mod( ) function description can be found here:
As I can see in the help document, mod has the function similar to division ,but not as you said. What is the reason?
mod
Modulus after division
Syntax
M = mod(X,Y)
Description
M = mod(X,Y) if Y ~= 0, returns X - n.*Y where n = floor(X./Y). If Y is not an integer and the quotient X./Y is within roundoff error of an integer, then n is that integer. The inputs X and Y must be real arrays of the same size, or real scalars.
The following are true by convention:
  • mod(X,0) is X
  • mod(X,X) is 0
  • mod(X,Y) for X~=Y and Y~=0 has the same sign as Y.
Generic code could be:
% Periodic triangle wave
amplitude = whatever;
period = whatever;
y = mod(x,period);
ix = y > period/2;
y(ix) = period - y(ix);
y = (amplitude * 2 / period) * y;
Yes, you are so great,thank you so much.

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More Answers (2)

y=zeros(size(x));
for k=1:5
y(x>=(k-1)*2&x<(k-1)*2+1)=x(x>=(k-1)*2&x<(k-1)*2+1);
y(x>=2*(k-1)+1&x<2*k)=2-x(x>=2*(k-1)+1&x<2*k);
end

4 Comments

Hi, thank you for your answer,but I find it is not the results that I want as you see in the image,
clc;
clear all;
x=linspace(0,10,100);
y=zeros(size(x));
for k=1:5
y(x>=(k-1)*2&x<(k-1)*2+1)=x(x>=(k-1)*2&x<(k-1)*2+1);
y(x>=2*(k-1)+1&x<2*k)=2-x(x>=2*(k-1)+1&x<2*k);
end
plot(x,y)
Are your functions changing? Recommend showing us the input and output you want.
Then just use the code that you used to create the figure. It's what you want isn't it?
Please see the below image I upload,it is what I want.

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x = [0:3:36];
y = [0 1 0 1 0 1 0 1 0 1 0 1 0];
sig = pwfun(x,y);
and create the waveform only with the intersection points.

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