Creating an 8x8 matrix using loops
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Hello eveyone,
I wanted to learn how to create an 8x8 matrix like how it's represented with the pic. I can create it using reshape() bu I want to get the same output using loops.How's that
possible? For and if loop to be more spesific.
1 Comment
Ameer Hamza
on 22 Nov 2020
What have you already tried for your homework question: https://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer
Answers (2)
KSSV
on 22 Nov 2020
Edited: KSSV
on 22 Nov 2020
Hints:
1. You can generate the number array using ':'. If I want numbers from 1 to 36. I will use
l = 1:36;
2. Once numbers are generated you can use reshape . Read about reshape .
3. After reshape , if the matrix is upside down; you can changed the order using flipud . Read about it.
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KALYAN ACHARJYA
on 22 Nov 2020
Edited: KALYAN ACHARJYA
on 22 Nov 2020
"I can create it using reshape() but I want to get the same output using loops.How's that possible? For and if loop to be more spesific"
You can do that multiple ways, without using any other function, like flip, rot etc. One Way
data=1:64;
mat=zeros(8,8);
k=1;
for i=8:-1:1
idx=k+7*(k-1);
mat(i,:)=data(idx:idx+7);
k=k+1;
end
mat
Please make it more simpler
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