How do i create an array with a for loop?
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Brendan Querey
on 17 Nov 2020
Commented: Walter Roberson
on 17 Nov 2020
I'm trying to create a an array of ten numbers randomly generate from a normal distribution, and I also need the initial number to not have the same function as the remaining 9.
P_t = normrnd(72.7,7.6);
p_t = normrnd(12.6,3.9);
price = zeros(10:1);
for n = 1:10
if n == 1
price(n) = P_t;
else
price(n) = .8 * P_t + p_t;
end
end
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Accepted Answer
Walter Roberson
on 17 Nov 2020
Edited: Walter Roberson
on 17 Nov 2020
P_t = @() normrnd(72.7,7.6);
p_t = @() normrnd(12.6,3.9);
price = zeros(10,1);
for n = 1:10
if n == 1
price(n) = P_t();
else
price(n) = .8 * P_t() + p_t();
end
end
2 Comments
Walter Roberson
on 17 Nov 2020
@() introduces the definition of an anonymous function that does not expect any parameters.
In the above code, each time P_t() is encountered, it would execute the function body, normrnd(72.7,7.6) , generating a new random number with the given distribution.
The code you were using was generating one single random number from each of the two distributions, and then using that same number for each iteration.
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