MATLAB Answers

Changing annotation size or font

3 views (last 30 days)
Nadine Nassar
Nadine Nassar on 15 Nov 2020
Commented: Mario Malic on 15 Nov 2020
Hello,
I'm having trouble fixing the annotations on my graph. For the annotations at the throat and exit, the value isn't that clear. Is there any reason why it's like this, and if I can change it so it's more clear? I've attached the code and a picture of my plot.
Thanks in advance
plot(i,r1(l), '.b'); hold on
plot(i,r2(l),'.b'); hold on
yline(0,'-.k');
xline(0,'-.r');
xline(-L/2,'-.r');
xline(L,'-.r');
title ('Plot of Nozzle Shape');
xlabel('Axial distance from the throat (mm)');
ylabel('Radius (mm)');
txt1 = ['Throat, d=' num2str(2*min(r1)) 'mm'];
text(0,1,txt1);
txt2 = ['Inlet, d=' num2str(2*r1(1)) 'mm'];
text(-L/2,1,txt2);
txt3 = ['Exit, d=' num2str(2*r1(end)) 'mm'];
text(0.85*L,1,txt3)

  0 Comments

Sign in to comment.

Accepted Answer

Mario Malic
Mario Malic on 15 Nov 2020
Is your piece of code in for loop?
Guessing that r1(1) and r1(end) are changing and there are many different texts on top of each other.

  4 Comments

Show 1 older comment
Mario Malic
Mario Malic on 15 Nov 2020
For the sake of people who are reading your code in future, please don't use lowercase character 'L' as your index, I thought it was number '1'.
Put this outside of for loop and it should work.
txt1 = ['Throat, d=' num2str(2*min(r1)) 'mm'];
text(0,1,txt1);
txt2 = ['Inlet, d=' num2str(2*r1(1)) 'mm'];
text(-L/2,1,txt2);
txt3 = ['Exit, d=' num2str(2*r1(end)) 'mm'];
text(0.85*L,1,txt3)
However, you should avoid using for loop here, and simplify your code. I think this would get you the same r you have at the end of your loop.
i=(-L/2):2:L
r=(r_throat^2)*(1 + (2.5*((i/L).^2)));
Nadine Nassar
Nadine Nassar on 15 Nov 2020
Okay, i'll change it. I also tried your suggestion of not using a for loop and I got the same results, and realised the computational time was much faster this time. The text on the plot is also fixed now.
Thanks a lot for yor help
Mario Malic
Mario Malic on 15 Nov 2020
Cool! You're welcome.

Sign in to comment.

More Answers (0)

Categories

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!