How can generalize severel "For loop" ?

for i=1:n

L(i,i)=1;

end

for i=2:n

L(i,1)=A(i,1)/A(1,1);

end

for i=3:n

L(i,2)=A(i,2)/A(2,2);

end

for i=4:n

L(i,3)=A(i,3)/A(3,3);

end

[Mark Whirdy]

Hi there

What are the values of A & n?

Could you values for all variables and the required output as well as describing what you are trying to do?

[José-Luis]

This is the second time in less than an hour that the same question has been asked in the forum. Looks like the instructor recommended Matlab answers. This can be done in a rather straightforward way. Please read the "Getting started" part of the documentation and ask specific questions whenever you encounter problems. People will be happy to help you then.

Answer 1

[Sean de Wolski]

Use a nested for loop:

for ii = 1:n
   for jj = ii:n
       stuff
   end
end

Answer 2

[STamer]

A=input('Enter nxn matrix:')

B=input('Enter solution matrix(n*1):')

[n n]=size(A);

L=zeros(n);

for i=1:n

L(i,i)=1;

end

for i=2:n

L(i,1)=A(i,1)/A(1,1);

end

for i=3:n

L(i,2)=A(i,2)/A(2,2);

end

for i=4:n

L(i,3)=A(i,3)/A(3,3);

end