why this error ??

x=[-90 -90 -90 -90 -90 -45 -45 -45 -45 -45 0 0 0 0 0 45 45 45 45 45 90 90 90 90 90,45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45 45 22.5 0 -22.5 -45];
n=1;
when n<26;
f=0;
p=1/2*acosd(sqrt((1-sind(2*x(2,n))*sind(2*x(2,n)))/(1+tan(2*x(1,n))*tand(2*x(1,n)))));
ax=sqrt(1/(tand(p)*tand(p)+1));
ay= sqrt(1-ax^2);
d=acosd(tan(2*x(1,n))*sqrt((1-(sind(2*x(2,n))*sind(2*x(2,n))))/(tan(2*x(1,n))+((sind(2*x(2,n)))*(sind(2*x(2,n)))))));
f1=['simulation ',num2str(n)];
disp(f1);
f2=['ax=',num2str(ax),' ','ay=',num2str(ax),' ','d=',num2str(ax),' ','p=',num2str(p)];
disp(f2);
n = n+1;
end
Index in position 1 exceeds array bounds (must not exceed 1).

Answers (2)

Alan Stevens
Alan Stevens on 16 Oct 2020

0 votes

You have defined x as a 1x25 vector, but you are calling it with two arguments. You need to call it with x(n), rather than x(1,n) and x(2,n).
You probably also should use "while" rather than"when".
Image Analyst
Image Analyst on 16 Oct 2020
x has only one row, not two. So what value are you thinking of when you try to get the value in row 2, column n? Why do you think there should even be a x(2, n)???
Plus you must use while instead of when, or else just use a for loop
for n = 1 : 25

Asked:

on 16 Oct 2020

Answered:

on 16 Oct 2020

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