Gas-Solid Reaction Modeling with Random Pore Model. Pdepe: Spatial discretization has failed. Discretization supports only parabolic and elliptic equations, with flux term involving spatial derivative.
4 views (last 30 days)
Show older comments
VINCENZO MAIELLO
on 15 Sep 2020
Edited: VINCENZO MAIELLO
on 8 Oct 2020
Hello everyone,
I am studying the reaction's kinetics of calcium oxide with carbon dioxide through the Random Pore Model of Bhatia and Perlmutter. You can find the equations and code attached that I am trying to solve with the pdepe but it appears the error "Error using pdepe (line 293) Spatial discretization has failed. Discretization supports only parabolic and elliptic equations, with flux term involving spatial derivative".
Is there anyone who could tell me why I have this kind of error in the code and how to fix it?
Thanks in advance for your help.
clc,clear
%% RPM
% Properties
global phi zeta beta psi eps0 cb ceq s0 ks Sh
R=41e-6; %[m]
cb=1.95e-5; %[kmol m^-3]
ks=0.559e-5; %[m^4 kmol^-1 s^-1]
ceq=1.93e-3; %[kmol m^-3]
s0=42e6; %[m^-1]
psi=1.52; %[-]
zeta=2.10; %[-]
eps0=0.47; %[-]
beta=8120; %[-]
phi=45.46; %[-]
Sh=4.48; %[-]
%Axes
rmesh=linspace(0,R,100);
etamesh=rmesh/R; %eta
tspan=linspace(-1523,0,100);%tetac
%% Solver
m=2;
sol=pdepe(m,@pdefun,@icfun,@bcfun,etamesh,tspan);
cstar=sol(:,:,1);
xcao=sol(:,:,2);
%% Plots
surf(etamesh,tspan,sol,'edgecolor','none')
xlabel('xcao [-]')
ylabel('deltatetac [-]')
zlabel('c* [-]')
% Pdefun
function [c,f,s] = pdefun(x,t,u,dudx)
global phi zeta beta psi eps0 cb ceq s0 ks Sh
cs=u(1);
xcao=u(2);
c=[-phi^2 1]';
f=[1-((zeta-1)*(1-eps0)/eps0)*xcao 0]'.*dudx;
s=[0 -(cs*(1-xcao)*(1-psi*log(1-xcao)^(0.5)))/(1+((beta*zeta)/(psi)*(1-psi*log(1-xcao))^(0.5)-1))]';
end
% Bcfun
function [pl,ql,pr,qr] = bcfun(xl,ul,xr,ur,t)
global phi zeta beta psi eps0 cb ceq s0 ks Sh
pl = [0 0]';
ql = [1 1]';
pr=[0 0]';
qr =[0 0]' ;
end
% Icfun
function u0 = icfun(x)
global phi zeta beta psi eps0 cb ceq s0 ks Sh
u0 =[-ceq/(cb-ceq) 0]';
end
0 Comments
Accepted Answer
Bill Greene
on 15 Sep 2020
Your right-end boundary conditions are invalid.
Possibly you want:
pr=[ur(1)-1 0]';
qr =[0 1]' ;
More Answers (0)
See Also
Categories
Find more on Eigenvalue Problems in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!