Finding min values of third column for rows with similar values
1 view (last 30 days)
Show older comments
ahmad Mohammadi
on 10 Aug 2020
Edited: ahmad Mohammadi
on 11 Aug 2020
Hi,
I have a Table
2.0000 0 3.1971
1.0000 0 3.1971
3.0000 0 6.4662
1.0000 0 6.4662
3.0000 0 9.6356
2.0000 0 9.6356
2.0000 1 7
1.0000 1 5
3.0000 1 6
1.0000 1 10
3.0000 1 44
2.0000 1 12
Now, what I want is that find minimum value of third column for the first column with equal value in each loop of second column.
Maybe it is better to see the result what I mean.
2.0000 0 3.1971
1.0000 0 3.1971
3.0000 0 6.4662
2.0000 1 7
1.0000 1 5
3.0000 1 6
Really appreciate
1 Comment
Stephen23
on 11 Aug 2020
Edited: Stephen23
on 11 Aug 2020
The example is not clear for me. You wrote that you want the "...minimum value of third column...", can you please explain why your example output contains this row:
...
2.0000 1 7
...
when the input matrix contains both of these rows
...
2.00000 1.00000 7.00000
...
2.00000 1.00000 2.00000
As far as I can tell, 2 is less than 7, so why does the expected output not contain the "minimum value" ?
Accepted Answer
Stephen23
on 11 Aug 2020
Edited: Stephen23
on 11 Aug 2020
>> M = [2.0000,0,3.1971;1.0000,0,3.1971;3.0000,0,6.4662;1.0000,0,6.4662;3.0000,0,9.6356;2.0000,0,9.6356;2.0000,1,7;1.0000,1,5;3.0000,1,6;1.0000,1,10;3.0000,1,44;2.0000,1,2]
M =
2.0000 0 3.1971
1.0000 0 3.1971
3.0000 0 6.4662
1.0000 0 6.4662
3.0000 0 9.6356
2.0000 0 9.6356
2.0000 1.0000 7.0000
1.0000 1.0000 5.0000
3.0000 1.0000 6.0000
1.0000 1.0000 10.0000
3.0000 1.0000 44.0000
2.0000 1.0000 2.0000
>> [U,X,Y] = unique(M(:,1:2),'stable','rows');
>> V = accumarray(Y,M(:,3),size(X),@min);
>> A = [U,V]
A =
2.0000 0 3.1971
1.0000 0 3.1971
3.0000 0 6.4662
2.0000 1.0000 2.0000
1.0000 1.0000 5.0000
3.0000 1.0000 6.0000
You might need to consider using https://www.mathworks.com/help/matlab/ref/uniquetol.html
More Answers (1)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!