plot curve in matlab

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saman ahmadi on 8 Aug 2020

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Hi. How can i plot below equation? please help me

I want to plot h against qa

thank you

h=(611375/279 - ((192500000*cos(qa))/93 + ((60000*cos(qa))/31 - 611375/93)^2/9 - 14656250/31)/(2*((153125000000*cos(qa))/31 - (((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 + (((((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 - (153125000000*cos(qa))/31 + ((60000*cos(qa))/31 - 611375/93)^3/27 + 153125000000/31)^2 - ((192500000*cos(qa))/93 + ((60000*cos(qa))/31 - 611375/93)^2/9 - 14656250/31)^3)^(1/2) - ((60000*cos(qa))/31 - 611375/93)^3/27 - 153125000000/31)^(1/3)) - (3^(1/2)*(((192500000*cos(qa))/93 + ((60000*cos(qa))/31 - 611375/93)^2/9 - 14656250/31)/((153125000000*cos(qa))/31 - (((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 + (((((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 - (153125000000*cos(qa))/31 + ((60000*cos(qa))/31 - 611375/93)^3/27 + 153125000000/31)^2 - ((192500000*cos(qa))/93 + ((60000*cos(qa))/31 - 611375/93)^2/9 - 14656250/31)^3)^(1/2) - ((60000*cos(qa))/31 - 611375/93)^3/27 - 153125000000/31)^(1/3) - ((153125000000*cos(qa))/31 - (((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 + (((((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 - (153125000000*cos(qa))/31 + ((60000*cos(qa))/31 - 611375/93)^3/27 + 153125000000/31)^2 - ((192500000*cos(qa))/93 + ((60000*cos(qa))/31 - 611375/93)^2/9 - 14656250/31)^3)^(1/2) - ((60000*cos(qa))/31 - 611375/93)^3/27 - 153125000000/31)^(1/3))*1i)/2 - ((153125000000*cos(qa))/31 - (((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 + (((((60000*cos(qa))/31 - 611375/93)*((192500000*cos(qa))/31 - 43968750/31))/6 - (153125000000*cos(qa))/31 + ((60000*cos(qa))/31 - 611375/93)^3/27 + 153125000000/31)^2 - ((192500000*cos(qa))/93 + ((60000*cos(qa))/31 - 611375/93)^2/9 - 14656250/31)^3)^(1/2) - ((60000*cos(qa))/31 - 611375/93)^3/27 - 153125000000/31)^(1/3)/2 - (20000*cos(qa))/31)^(1/2)