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Can anyone explain me why M' is taken in the following code?

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%{
Question : Write a function called minimax that takes M, a matrix input argument and
returns mmr, a row vector containing the absolute values of the difference
between the maximum and minimum valued elements in each row. As a second
output argument called mmm, it provides the difference between the maximum
and minimum element in the entire matrix
%}
%Code :
function [mmr, mmm] = minimax(M)
mmr = max(M') - min(M');
mmm = max(M, [], 'all') - min(M, [], 'all');
  5 Comments

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Answers (5)

Walter Roberson
Walter Roberson on 2 Aug 2020
By default, min() and max() operate along the first non-scalar dimension. If you have a 2D array, m x n, with m and n both not 1, then that means that min() or max() of the array would produce a 1 x n output -- it has operated along columns, producing one result for each column.
Now suppose you transpose the m x n array to become n x m, with the rows becoming columns and the columns becoming rows, and you min() or max that. You will get a 1 x m result -- one result for each of what were originally rows.
Thus, min(M') is one way of producing a minimum for each row (but it has a problem if the data is complex-valued.)
More clear and robust is to use the syntax min(M,[],2) to process dimension #2 specifically, producing one result for each row.

Shubham Shah
Shubham Shah on 22 Dec 2022
function [mmr,mmm]= minimax(M)
mmt = [max(M,[],2)-min(M,[],2)]
mmr = mmt'
mmm = max(M, [], 'all') - min(M, [], 'all')
end
  2 Comments
Shubham Shah
Shubham Shah on 22 Dec 2022
Question : Write a function called minimax that takes M, a matrix input argument and
returns mmr, a row vector containing the absolute values of the difference
between the maximum and minimum valued elements in each row. As a second
output argument called mmm, it provides the difference between the maximum
and minimum element in the entire matrix
Stephen23
Stephen23 on 28 Oct 2023
Edited: Stephen23 on 28 Oct 2023
Nice, but why the superfluous square brackets and no semi-colons?

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Abdul Rafay
Abdul Rafay on 28 Oct 2023
function [mmr,mmm] = minimax(A)
mmr = max(A')-min(A');
a = A(:);
mmm = max(a)-min(a);
end
  1 Comment
Stephen23
Stephen23 on 28 Oct 2023
Edited: Stephen23 on 28 Oct 2023
Fails for any column vector:
[adr,dom] = minimax([1;2;3])
adr = 2
dom = 2
function [mmr,mmm] = minimax(A)
mmr = max(A')-min(A');
a = A(:);
mmm = max(a)-min(a);
end
Tip for the future: read the thread thoroughly before posting anything new:

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Japhet Kyarukamba
Japhet Kyarukamba on 20 Apr 2024
Edited: Japhet Kyarukamba on 20 Apr 2024
% function // editor window
function [mmr, mmm] = minimax(A)
mmr = max(A, [], 2) - min(A, [], 2); % Compute maximum and minimum along rows
a = A(:); % Reshape A into a column vector to find the absolute difference over the entire matrix
mmm = max(a)-min(a); % Find the maximum and minimum values across the entire matrix
end
% Code to call your function? // command window
[mmr, mmm] = minimax([1:3;4:6;7:9])
mmr = 3x1
2 2 2
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
mmm = 8
% Generate a random matrix of size 1x3 with integers between 1 and 100
random_matrix = randi([1, 100], 1, 3)
random_matrix = 1x3
12 80 1
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>

Japhet Kyarukamba
Japhet Kyarukamba on 20 Apr 2024
Alternatively,
% function // editor window
function [mmr, mmm] = minimax(M)
% Transpose M to work on each row, then calculate the differences.
mmr = max(M') - min(M'); % Calculate the absolute differences between maximum and minimum elements in each row.
mmm = max(M, [], 'all') - min(M, [], 'all') % Calculate the absolute difference between maximum and minimum elements in the entire matrix.
end
% Code to call your function? // command window
[mmr, mmm] = minimax([1:3;4:6;7:9])
mmm = 8
mmr = 1x3
2 2 2
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
mmm = 8
% Generate a random matrix of size 1x3 with integers between 1 and 100
random_matrix = randi([1, 100], 1, 3)
random_matrix = 1x3
89 34 1
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
  1 Comment
Stephen23
Stephen23 on 20 Apr 2024
Fails for any column vector:
[adr,dom] = minimax([1;2;3])
adr = 2
dom = 2
function [mmr, mmm] = minimax(M)
% Transpose M to work on each row, then calculate the differences.
mmr = max(M') - min(M'); % Calculate the absolute differences between maximum and minimum elements in each row.
mmm = max(M, [], 'all') - min(M, [], 'all'); % Calculate the absolute difference between maximum and minimum elements in the entire matrix.
end
Tip for the future: read the thread thoroughly before posting anything new:

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