# Can anyone explain me why M' is taken in the following code?

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%{

Question : Write a function called minimax that takes M, a matrix input argument and

returns mmr, a row vector containing the absolute values of the difference

between the maximum and minimum valued elements in each row. As a second

output argument called mmm, it provides the difference between the maximum

and minimum element in the entire matrix

%}

%Code :

function [mmr, mmm] = minimax(M)

mmr = max(M') - min(M');

mmm = max(M, [], 'all') - min(M, [], 'all');

##### 5 Comments

Stephen23
on 22 Dec 2022

### Answers (2)

Walter Roberson
on 2 Aug 2020

By default, min() and max() operate along the first non-scalar dimension. If you have a 2D array, m x n, with m and n both not 1, then that means that min() or max() of the array would produce a 1 x n output -- it has operated along columns, producing one result for each column.

Now suppose you transpose the m x n array to become n x m, with the rows becoming columns and the columns becoming rows, and you min() or max that. You will get a 1 x m result -- one result for each of what were originally rows.

Thus, min(M') is one way of producing a minimum for each row (but it has a problem if the data is complex-valued.)

More clear and robust is to use the syntax min(M,[],2) to process dimension #2 specifically, producing one result for each row.

##### 0 Comments

Shubham Shah
on 22 Dec 2022

function [mmr,mmm]= minimax(M)

mmt = [max(M,[],2)-min(M,[],2)]

mmr = mmt'

mmm = max(M, [], 'all') - min(M, [], 'all')

end

##### 1 Comment

Shubham Shah
on 22 Dec 2022

Question : Write a function called minimax that takes M, a matrix input argument and

returns mmr, a row vector containing the absolute values of the difference

between the maximum and minimum valued elements in each row. As a second

output argument called mmm, it provides the difference between the maximum

and minimum element in the entire matrix

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