Displaying cells which have different sizes
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Hi everyone. Lets say I have a cell. I tried different ways but I could'nt make it properly.
Y{1,1}=['WATER'] Y{2,1}=2
Y{2,1}=['WATER' 'COKE'] Y{2,2}=3
my code to display these are ;
a=0;
while (a<length(Y))
a=a+1;
disp(['#' num2str(a) ':' (Y{a,1}) ' GET-->' mat2str(Y{a,2})])
end
RESULT
'#' '1' ':' 'WATER' 'GET-->' '2'
'#' '2' ':' 'WATER' 'COKE' 'GET-->' '3'
How can I get something like that
#1 : 'WATER' GET--> 2
#1 : 'WATER' 'COKE' GET--> 3
0 Comments
Answers (2)
madhan ravi
on 9 Jul 2020
for k= 1:size(Y,1)
fprintf('#1 : %s GET--> %d\n', Y{k,1}, Y{k,2})
end
3 Comments
madhan ravi
on 9 Jul 2020
clear all
Y{1,1}=['WATER']
Y{1,2}=2
Y{2,1}=['WATER', 'COKE']
Y{2,2}=3
for k= 1:size(Y,1)
s = repmat('%s', 1, numel(Y{k,1}));
fprintf('#1 :',s,' GET--> %d\n', Y{k,1}, Y{k,2})
end
Image Analyst
on 9 Jul 2020
Try this:
Y = {1, 'WATER', []; ...
1, 'WATER', 'COKE'}
You get:
Y =
2×3 cell array
{[1]} {'WATER'} {0×0 double}
{[1]} {'WATER'} {'COKE' }
The 1,3 cell is still there since you can't have missing elements in an array. Like any array, cell arrays included, you can't have 2 columns in the first row and 3 columns in the second row.
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